view contrib/wochenbericht @ 568:e7b36e596751 tip

Last week's year is not necessarily today's year
author Tom Gottfried <tom@intevation.de>
date Mon, 03 Jan 2022 11:37:31 +0100
parents d80f40d239d2
children
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#!/bin/bash
#
# wochenbericht
# -------------
# (c) 2008 by Sascha L. Teichmann

# Little script to summarize times within a given week.
# usage:
# ./wochenbericht [<week of year>] [<getan database file>]
# week defaults to current week, database to time.db
#
# This is Free Software in terms of GPLv3 or later. See
# LICENSE coming with getan for details.
#
usage() {
    cat <<EOF
usage: ./wochenbericht [<week of year>] [<year>] [<getan database file>] 
    <week of year>        defaults to current week
    <year>                defaults to current year
    <getan database file> defaults to time.db
EOF
    exit 1
}

if [ "$1" ==  "--help" -o "$1" == "-h" ]; then
    usage
fi


if [[ "$1" -eq "" ]]; then
    WEEK=`date +'%W'`
    # remove hash below if you want previous week
    #WEEK=`expr ${WEEK} '-' 1 '|' 52`
else
    WEEK=$1
fi

if [[ "$2" -eq "" ]]; then
    YEAR=`date +'%Y'`
else
    YEAR=$2
fi

TIME_DB=${3:-time.db}

if [ ! -f ${TIME_DB} ]; then
    echo "error: Database file ${TIME_DB} does not exist."
    usage
fi

sqlite3 ${TIME_DB} "
SELECT coalesce(description, 'Verschiedenes'), total FROM projects 
INNER JOIN (
    SELECT 
        project_id,
        sum(strftime('%s', stop_time) - strftime('%s', start_time)) AS total
    FROM entries
    WHERE (strftime('%W', start_time) = '${WEEK}' AND
        strftime('%Y', start_time) = '${YEAR}') OR 
        (strftime('%W', stop_time)  = '${WEEK}' AND
        strftime('%Y', stop_time) = '${YEAR}')
    GROUP BY project_id
) ON id = project_id
WHERE active;
" | awk '
function human_time(t) {
    h = int(t / 3600)
    m = int((t % 3600)/60.0 + 0.5)
    while (m >= 60) { ++h; m -= 60 }
    return sprintf("%2d:%02dh", h, m)
}
BEGIN { FS="|"; sum = 0 }
      { sum += $2 
        printf("%s: %s\n", human_time($2), $1) 
      }
END   { printf("%s: Gesamt\n", human_time(sum)) } 
'
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